A stone is dropped from the edge of a roof, and hits the ground with a velocity of −165 feet per second. Assume the acceleration due to gravity is -32 feet per second squared. How high (in feet) is the

asked Jan 5, 2023 182k views

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2 votes

Answer:

425.39 ft

Explanation:

$(1)/(2)mv^2=mgh\\(1)/(2)v^2=gh\\v^2=2gh$

h =
(v^2)/(2g) = (165^2)/(2 * 32)=(27225)/(64)=425.39ft

Irshad Bhat answered Jan 10, 2023

5.9k points

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