Question

A stone is dropped from the edge of a roof, and hits the ground with a velocity of −165 feet per second. Assume the acceleration due to gravity is -32 feet per second squared. How high (in feet) is the roof?

Answer 1

425.39 ft

Explanation:

`(1)/(2)mv^2=mgh\\(1)/(2)v^2=gh\\v^2=2gh`

h =
`(v^2)/(2g) = (165^2)/(2 * 32)=(27225)/(64)=425.39ft`