Question

The population of bulford was 16,200 in 2010 and 13,824 in 2016. find the rate of change

Answer 1

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

`\begin{array}cc \cline{1-2} \stackrel{x}{year}&\stackrel{y}{population}\\ \cline{1-2} 2010&16200\\ 2016&13824\\ \cline{1-2} \end{array}\hspace{5em} (\stackrel{x_1}{2010}~,~\stackrel{y_1}{16200})\qquad (\stackrel{x_2}{2016}~,~\stackrel{y_2}{13824}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{13824}-\stackrel{y1}{16200}}}{\underset{run} {\underset{x_2}{2016}-\underset{x_1}{2010}}} \implies \cfrac{ -2376 }{ 6 } \implies \text{\LARGE -396} ~~ \textit{per year}`