Question

One antifreeze solution is 41% alcohol and another is 11% alcohol. How much of each mixture should be added to make 30 L of a solution that is 29% alcohol?

Answer 1

18 liters of 41% alcohol and 12 liters of 11% alcohol.

Explanation:

.41x + .11(30-x) = .29(30) I am going the clear the decimal by multiply all the way through by 100

41x + 11(30 -x ) = 29(30)

41x + 330 -11x = 875 Combine like terms

30x +330 = 875 Subtract 330 from both sides

30x = 540 Dived both sides by 30

x = 18

30 - 18 = 12

Amount Percent Total

x .41 .41x

30 - x .11 .11(30 - x)

30 .29 .29(30)

Look at the total column

.41x + .11(30-x) = .29(30)