Question

The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?​

Answer 1

Step by step:

Perimeter = Summation of all sides = AB+BC+CD+DA = 2x+2+x+2x+2+x=(6x+4)

⇒6x+4=154

⇒6x=154−4

⇒
`(150)/(6x)`

⇒25=x

The breadth is x=25

The length of the rectangular pool = (2×25+2)=50+2=52m

breadth is 25 and the length is 52

Hope it helps!

Answer 2

`\blue\star \rm\pink{ Question:}`

The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?

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`\blue\star \rm\pink{ Given :}`

• Perimeter of swimming pool is 154 m
• Length is 2m more than breadth

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`\blue\star \rm\pink{ To ~Find :}`

• Length of rectangular pool
• Breadth of rectanglur pool

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`\blue\star \rm\pink{Let :}`

• Breadth of x
• Length be (2 + 2x)

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We know:-

`\bigstar \boxed{ \rm perimeter \: of \: rextangle = 2(length +breadth)}`

So:-

`\\ \\`

`\dashrightarrow\sf perimeter \: of \: rextangle = 2(length +breadth) \\`

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`\dashrightarrow\sf 154 = 2( 2 + 2x +x) \\`

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`\dashrightarrow\sf 154 = 2( 2 + 3x) \\`

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`\dashrightarrow\sf 154 = 2( 2 )+ 2(3x) \\`

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`\dashrightarrow\sf 154 = 4+ 2(3x) \\`

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`\dashrightarrow\sf 154 = 4+ 6x`

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`\dashrightarrow\sf 154 - 4 =6x`

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`\dashrightarrow\sf 150 =6x`

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`\dashrightarrow\sf 6x = 150`

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`\dashrightarrow\sf x = (150)/(6)`

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`\dashrightarrow\sf x = \cancel (150)/(6)`

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`\dashrightarrow\bf x =25`

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Let's Verify value of x:-

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`\dashrightarrow\sf 154 = 2( 2 + 2x +x) \\`

put value of x in equation

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`\dashrightarrow\sf 154 = 2( 2 + \{2 * 25 \} +25) \\`

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`\dashrightarrow\sf 154 = 2( 2 + 50+25) \\`

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`\dashrightarrow\sf 154 = 2( 2 + 75) \\`

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`\dashrightarrow\sf 154 = 2(77) \\`

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`\dashrightarrow\bf 154 =154`

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`\Large \bf\dag LHS = RHS \dag`

Hence proved

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Finally Let's find length and breadth of pool:-

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To find breadth

➙ Breadth = x

➙ Breadth = 25 m

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To find length

➙ Length = 2 + 2x

➙ Length = 2 + 2(25)

➙ Length = 2 + 50

➙ Length = 52 m

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Cheers! all done. :)