Question

You are standing on the ground (height of 0) and kick a ball across the park with an initial velocity of 64 feet per second. Using the vertical motion model, calculate each of the following: Don't forget units

a. What is the highest height the ball reaches?

b. When will the ball be at the highest height?

c. How long is the ball in the air?

I need this question to be answered it's 30 points and please no links just leave the answer

Answer 1

a. The highest height the ball reaches is 7.35 meters. b. The ball will be at the highest height after 1.22 seconds. c. The ball is in the air for 2.45 seconds.

Step-by-step explanation:

a. To find the highest height the ball reaches, we can use the vertical motion model equation: h = v1y2 / (2g), where h is the height, v1y is the vertical component of the initial velocity, and g is the acceleration due to gravity. Since the initial velocity has a vertical component of 12 m/s, and the acceleration due to gravity is approximately 9.8 m/s2, we can substitute these values into the equation to find the highest height the ball reaches: h = (122) / (2 imes 9.8) = 7.35 meters.

b. To calculate when the ball will be at the highest height, we can use the equation: t = v1y / g, where t is the time, v1y is the vertical component of the initial velocity, and g is the acceleration due to gravity. Substituting the given values, we get: t = 12 / 9.8 = 1.22 seconds.

c. To determine how long the ball is in the air, we can use the equation t = 2v1y / g, where t is the time, v1y is the vertical component of the initial velocity, and g is the acceleration due to gravity. Plugging in the values, we have: t = 2 imes 12 / 9.8 = 2.45 seconds.