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Answer:
A: 8 ft²
B: draw diagonal AC; 4 ft²
Explanation:
Part A: The area is given by the formula ...
A = bh . . . . . . . the product of base and height dimensions
A = (9 ft)(8/9 ft) = 8 ft² . . . . area of the parallelogram
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Part B:
Either diagonal (AC or BD) will divide the parallelogram into two congruent triangles, each with the same base and height as the parallelogram. It is no surprise, then, that the area of either of those triangles is ...
A = 1/2bh
A = 1/2(9 ft)(8/9 ft) = 4 ft² . . . . . . area of triangular half of parallelogram
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AC divides the figure into congruent acute triangles; BD divides it into congruent obtuse triangles.