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What are the minimum and maximum of values of t for which |t+3|≤2 ?

User Psmagin
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1 Answer

6 votes

Answer:

Minimum Value: -5

Maximum Value: -1

Interval is [-5, -1]

Explanation:

In math the absolute rule for a function f(x) = |x| ≤ a means that the range of values for x can be -a ≤ x ≤ +a

Use |t+3| instead of x in the above rule with a = 2

|t + 3| ≤ 2

⇒ -2 ≤ t + 3 ≤ 2


Subtract 3 from all parts
⇒ -2 - 3 ≤ t + 3 -3 ≤ 2 - 3
This gives

-5 ≤ t ≤ -1

which are the limits for t.

In interval notation this is
[-5, -1]
Minimum Value: - 5
Maximum Value: - 1

User Steven Kramer
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3.2k points