Question

If 1.3 moles of silicon dioxide react with 2.5 moles of carbon, how many grams of carbon

monoxide form?

Answer 1

46.76 g

Step-by-step explanation:

The reaction that takes place is:

• SiO₂ + 3C → SiC + 2CO

First we determine the limiting reactant:

1.3 moles of SiO₂ would react completely with (3 * 1.3) 3.9 moles of C. There are not as many C moles, meaning that C is the limiting reactant.

Now we convert C moles (the limiting reactant) into CO moles, using the stoichiometric coefficients:

• 2.5 mol C *
  `(2molCO)/(3molC)` = 1.67 mol CO

Finally we convert 1.67 moles of CO to grams, using its molar mass:

• 1.67 mol CO * 28 g/mol = 46.76 g