Question

Find two consecutive even integers such that 5 more than half of the larger number is 8 less than the smaller number.

Answer 1

The two numbers:

27 and 28

Explanation:

a = first number

a+1 = consecutive

5 + (a+1)/2 = a - 8

(a+1)/2 = a - 8 - 5

(a+1)/2 = a-13

a+1 = 2(a-13)

a+1 = 2*a + 2*-13

a+1 = 2a - 26

a - 2a = -26 - 1

-a = -27

a = 27

a+1 = 28

Check:

5 + (28)/2 = 27 - 8

5 + 14 = 19