Question

1 = csc ө + cot² 0 ө

Answer 1

30 or -90

Explanation:

cot²x + cscx =1

But; 1+cot²x=csc²x (trigonometric identity)

hence cot²x=csc²x -1

(csc²x -1)+cscx=1

csc²x + cscx -1-1=0

csc²x + cscx - 2=0

let M=cscx

M²+M-2=0

M²+M-2M-2=0

(M-2)(M+1)=0

M=2 or M=-1

• when M= 2

cscx=2

1/sinx = 2

2sinx =1

sinx=1/2

x=30°

• when M= -1

cscx= -1

1/sinx = -1

sinx= -1

x=-90 (it's negative because the sine inverse of a number produces a negative angle)

Answer 2

Answer:90

Explanation: