Question

Given a center of (3,-5) and a radius of 4, write an equation for the circle.

Answer 1

(x-3)²+(y+5)²=16

Explanation:

`\large \boxed{ {(x - h)}^(2) + {(y - k)}^(2) = {r}^(2) }`

The equation above is an equation of circle with a centre at (h,k) and has radius = r

Substitute h = 3, k = -5 and r = 4 in the equation.

`\large{ {(x - 3)}^(2) + {(y - ( - 5))}^(2) = {4}^(2) } \\ \large{ {(x - 3)}^(2) + {(y + 5)}^(2) = 16}`