Question

If (x-1)^2 =8 then what is the value of (x+1)^2

Answer 1

`x=12+8\sqrt2\\\\x=12-8\sqrt 2`

Step by step explanation:

`\text{Given that,}\\\\~~~~~~~(x-1)^2 = 8\\ \\\implies x-1 =\pm\sqrt 8\\\\\implies x = \pm\sqrt 8 +1\\\\\text{Now,}\\\\~~~~(x+1)^2\\\\=\left(\pm\sqrt 8 +1 +1 \right)^2\\\\=(\pm\sqrt 8 +2)^2\\\\=\left(\pm \sqrt8 \right)^2 + 2 \left(\pm\sqrt 8 \right) \cdot 2 + 2^2\\\\=8+4+4\left(\pm\sqrt 8 \right)\\\\=12+4\left(\pm \sqrt 8\right)\\\\=12\pm 8\sqrt 2`