Question

at what speed do a bicycle and its rider, with a combined mass of 110 kgkg , have the same momentum as a 1600 kgkg car traveling at 5.8 m/sm/s ?

Answer 1

`v_1=84.36(m)/(s)`

Step-by-step explanation:

Momentum (p) is found by
`p=mv`

`p_1=m_1v_1\\p_2=m_2v_2`

So, the momentum of the objects will be the same when
`m_1v_1=m_2v_2`.

So, the speed at which the momentums are equal is represented by
`v_1=(m_1v_1)/(m_2)`.

`m_1=110kg\\m_2=1600kg\\v_2=5.8(m)/(s)\\v_1=((1600kg)(5.8(m)/(s)))/(110kg)\\v_1=84.36(m)/(s)`