Question

Find the minimum value of the function f(x)= x2+2.6x-2 to the nearest hundredth.

Answer 1

`(-1.3,-3.69)`

Explanation:

Take the derivative of the function and set it equal to 0.

`f(x)=x^2+2.6x-2`

`f'(x)=2x+2.6 = 0`

Solve for x.

`2x+2.6=0\\2x=-2.6\\x=-1.3`

Find
`f(-1.3)`

`f(-1.3)=(-1.3)^2+2.6(-1.3)-2`

`f(-1.3)=-3.69`