17.8k views
4 votes
Find the minimum value of the function f(x)= x2+2.6x-2 to the nearest hundredth.

1 Answer

3 votes

Answer:


(-1.3,-3.69)

Explanation:

Take the derivative of the function and set it equal to 0.


f(x)=x^2+2.6x-2


f'(x)=2x+2.6 = 0

Solve for x.


2x+2.6=0\\2x=-2.6\\x=-1.3

Find
f(-1.3)


f(-1.3)=(-1.3)^2+2.6(-1.3)-2


f(-1.3)=-3.69

User Julius Eckert
by
9.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories