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what is the empirical formula for ethyl fluoride if the compound contains 49.97% carbon, 10.51% hydrogen, and 39.52% fluorine by mass?

User Zlack
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Answer:

If the empirical formula for ethyl fluoride compound contains 49.97% carbon, 10.51% hydrogen, and 39.52% fluorine by mass so that means it would be C2H5F.

User Eneida
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