What is the empirical formula for ethyl fluoride if the compound contains 49.97% carbon, 10.51% hydrogen, and 39.52% fluorine by mass?

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Eneida · Answer 1 · 2023-03-11T02:42:16+0000

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If the empirical formula for ethyl fluoride compound contains 49.97% carbon, 10.51% hydrogen, and 39.52% fluorine by mass so that means it would be C2H5F.

What is the empirical formula for ethyl fluoride if the compound contains 49.97% carbon, 10.51% hydrogen, and 39.52% fluorine by mass?

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