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If 2x + 5y = -1 and 3x -2y = 27, then what is the value of x?

User Sirena
by
4.6k points

2 Answers

2 votes

Answer:

x = 7

Explanation:

Given system of equations:


\begin{cases}2x+5y=-1\\3x-2y=27\end{cases}

Multiply the first equation by 2:


\implies 2(2x+5y)=2(-1)


\implies 4x+10y=-2

Multiply the second equation by 5:


\implies 5(3x-2y)=5(27)


\implies 15x-10y=135

Add the two equations to eliminate the term in y:


\begin{array}{crcccl}& 4x & + & 10y & = & \:-2\\+ & (15x & - & 10y & = & 135)\\\cline{2-6} & 19x & & & = & 133\\\cline{2-6}\end{array}

Solve the equation for x:


\implies 19x=133


\implies (19x)/(19)=(133)/(19)


\implies x=7

User Ihammys
by
5.4k points
1 vote

Answer:

  • x = 7

--------------------------

Given system

  • 2x + 5y = - 1,
  • 3x - 2y = 27.

Eliminate y and solve for x

Multiply the first equation by 2 and the second equation by 5

  • 2(2x) + 2(5y) = 2(-1) ⇒ 4x + 10y = - 2
  • 5(3x) - 5(2y) = 5(27) ⇒ 15x - 10y = 135

Add up the equations

  • 4x + 15x = - 2 + 135
  • 19x = 133
  • x = 133/19
  • x = 7
User Bensonius
by
6.2k points