Question

A motor winches a 450.0 kg load of gravel for 15.0 s at a constant speed of 0.400 m/s

straight up vertically. How much work has the motor done on the box?

Answer 1

below

Step-by-step explanation:

The work done ( neglecting friction losses) is equal to the gain in Potential Energy

PE = mgh = 450 * 9.81 * (.400 * 15) = 26 487 J