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The perimeter of an ICU ward, that is rectangular in shape, is 258 feet. The width is 37 feet less than the length. Find the dimensions of this ward.

length(ft)=
width(ft)=

2 Answers

5 votes

Answer:

Length = 83 ft

Width = 46 ft

Explanation:

Rectangular perimeter = 2(length + width)

In this case:

258 = 2(length + width) Eq. 1

width = length - 37 Eq. 2

From Eq. 1:

258/2 = length + width

129 = length + width Eq. 3

Replacing Eq. 2 in Eq. 3

129 = length + (length-37)

129 + 37 = 2 length

166 = 2 length

166/2 = length

length = 83 ft

From Eq. 2:

width = length - 37

width = 83 -37

width = 46 ft

Check:

from Eq. 1:

258 = 2(width + length)

258 = 2(46 + 83)

258 = 2(129)

User Matlabgui
by
4.2k points
3 votes

Answer: length = 83, width= 46

Step-by-step explanation: 1. let's call the unknown dimensions x. We know that the formula for perimeter is 2(length) +2(width) so we can substitute.
2. After substituting, the equation should be 2(x) + 2(x-37)=258
3. Distribute. 2x+2x-74=258

4. Simplify. 4x-74=258

5. add 74 to both sides. 4x=332

6. x=83

7. We know that x was the length. The width was 37 less than the length (83). 83-37 is 46. So the length is 83, and the width is 46.


User Alex Tingle
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3.7k points