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Given the roots 2, -3, 4 that has to pass through the point (1, 10). What is the equation to this polynomial?

1 Answer

4 votes

Answer:
y=(5)/(6)(x-2)(x+3)(x-4)

Explanation:

Assuming this is a cubic polynomial, the equation in factored form is:


y=a(x-2)(x+3)(x-4)

Using the point
(1, 10) to solve for
a,


10=a(1-2)(1+3)(1-4)\\\\10=12a\\ \\ a=(5)/(6)\\\\\therefore y=(5)/(6)(x-2)(x+3)(x-4)

User Umar Dastgir
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