Question

Given the roots 2, -3, 4 that has to pass through the point (1, 10). What is the equation to this polynomial?

Answer 1

Answer:
`y=(5)/(6)(x-2)(x+3)(x-4)`

Explanation:

Assuming this is a cubic polynomial, the equation in factored form is:

`y=a(x-2)(x+3)(x-4)`

Using the point
`(1, 10)` to solve for
`a`,

`10=a(1-2)(1+3)(1-4)\\\\10=12a\\ \\ a=(5)/(6)\\\\\therefore y=(5)/(6)(x-2)(x+3)(x-4)`