Question

Find three consecutive odd integers such that ten more than 6 times

the first integers is equal to 4 less than 4 times the second.

pls show ur work

Answer 1

First number is -3

Second number is -1

Third number is 1

Explanation:

Let x = the first number

Let x +2 = the second number

Let x + 4 = the third number

6x + 10 = 4(x + 2) -4 Distribute the 4

6x + 10 = 4x + 8 -4 Combine like terms

6x + 10 = 4x + 4 Subtract 4x from both sides

2x + 10 = 4 Subtract 10 from both sides

2x = -6 Divide both sides by 2

x = -3

Next number -3 + 2 = -1

Third number

-3 + 4 = 1