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Heelllppp ppllzz !!!

Heelllppp ppllzz !!!-example-1
Heelllppp ppllzz !!!-example-1
Heelllppp ppllzz !!!-example-2
User Capo
by
3.5k points

1 Answer

2 votes

Answer:

m∠FLH = 66°

m∠EBF = 16°

Explanation:

Question 1

Given:

  • m∠FLG = 14x + 5
  • m∠HLG = 17x - 1

If LG bisects ∠FLH then m∠FLG = m∠HLG

⇒ 14x + 5 = 17x - 1

⇒ 6 = 3x

⇒ x = 2

Therefore, m∠HLG and m∠FLG = 33

m∠FLH = m∠FLG + m∠HLG

⇒ m∠FLH = 33 + 33 = 66°

Question 2

m∠ABE + m∠EBF = m∠ABF

⇒ 2b + m∠EBF = 7b - 24

⇒ m∠EBF = 7b - 24 - 2b

⇒ m∠EBF = 5b - 24

m∠ABE = m∠EBF

⇒ 2b = 5b - 24

⇒ -3b = - 24

⇒ b = 8

m∠EBF = 5b - 24

⇒ m∠EBF = 5(8) - 24 = 16

User David Richards
by
3.4k points