227k views
3 votes
Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the circle is 3 units. The center of the circle lies on the x-axis. The center of the circle lies on the y-axis. The standard form of the equation is (x – 1)² + y² = 3. The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

1 Answer

2 votes

Answer:

A, B, E

Explanation:

You want three true statements describing the circle whose equation is ...

x² + y² – 2x – 8 = 0

Graph

A graphing calculator can plot this equation for you. The result is attached.

We see that ...

  • The radius of the circle is 3 units.
  • The center of the circle lies on the x-axis.
  • The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

__

Additional comment

The standard form equation of a circle is ...

(x -h)² +(y -k)² = r² . . . . . center (h, k), radius r

Rearranging the given equation to this form, we have ...

(x -1)² +y² = 8 +1 = 9 . . . . . . . . r²=9 ⇒ r=3

This means the center is (1, 0), and the radius is 3. The point (1, 0) is on the x-axis.

The circle with equation x² + y² = 9 is centered at the origin and has radius 3.

Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true-example-1
User ComeRun
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories