What is y=x^2-9x+4 in vertex form?

Question

asked Sep 14, 2023 207k views

1 Answer

Na · Answer 1 · 2023-09-21T07:48:15+0000

Answer:

$y=\left(x^2-(9)/(2)\right)^2-(65)/(4)$

Explanation:

To put this in vertex form, we need to create a perfect square polynomial within the right side of the equation.

y=x^2-9x+4

$y=\left(x^2-9x + \left(-(9)/(2)\right)^2\right)+4 - (81)/(4)$

$y=\left(x^2-(9)/(2)\right)^2+4 - (81)/(4)$

$y=\left(x^2-(9)/(2)\right)^2-(65)/(4)$