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What is y=x^2-9x+4 in vertex form?

1 Answer

2 votes

Answer:


y=\left(x^2-(9)/(2)\right)^2-(65)/(4)

Explanation:

To put this in vertex form, we need to create a perfect square polynomial within the right side of the equation.


y=x^2-9x+4


y=\left(x^2-9x + \left(-(9)/(2)\right)^2\right)+4 - (81)/(4)


y=\left(x^2-(9)/(2)\right)^2+4 - (81)/(4)


y=\left(x^2-(9)/(2)\right)^2-(65)/(4)

User Na
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