Question

Find a so that the point (-1,5) is on the graph of f(x)=ax^2+2

Answer 1

a=3

Explanation:

To find a, you plug the known numbers into the given equation (coordinates). f(x) is the same as the y-coordinate.

With that, you get:

5=a(-1)^2+2

Then you solve for a

3=a(-1)^2

3=a(1)

3=a