Question

A 2.60 kg lion runs at a speed of 5.00 m/s until he sees his prey. The lion then speeds up 8.00 m/s to catch it. How much work did do after he speeds up?

Answer 1

Answer: 50.7 J

Step-by-step explanation:

Given

mass of lion is
`m=2.6\ kg`

The initial speed of the lion is
`v_1=5\ m/s`

increased speed of lion is
`v_2=8\ m/s`

Initially, its kinetic energy is
`K_1=(1)/(2)mv_1^2`

Final kinetic energy
`k_2=(1)/(2)mv_2^2`

work did by lion after speed up is
`k_2-k_1`

`\Rightarrow W=(1)/(2)* 2.6[8^2-5^2]\\\\\Rightarrow W=1.3* [39]=50.7\ J`