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A body moving with uniformly acceleration A has two point (5,15) and ( 20,60) on the velocity time graph of its motion. Calculate A. Pls I would like if the graph can be drawn I have the workings

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Answer:

3 m/s

Step-by-step explanation:

The slope of a velocity-time graph will give the acceleration for the object over the given interval.

Finding the slope:


a = (y_2 - y_1)/(x_2 - x_1) = (60 - 15)/(20 - 5) = (45)/(15) = 3\\

The acceleration A would be 3 m/s

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