Question

An arrow shot vertically upwards at a speed of 40m/s, hit the target after 2s. How high is the target? How fast did the arrow hit the target?​

Answer 1

Step-by-step explanation:

kinematics

d=V1*t + 1/2* a *
`t^(2)`

plug in your knowns into the above equation

d=40*2+1/2*(-9.8)*
`2^(2)`

60.4m

Vf = Vi+ a*t

Vf = 40 + (-9.8)*2

Vf = 20.4 m/s