Question

The diagram below shows a circle with centre 0. ACB is a tangent to the circle and DOE is 68* Find the angle EDC. You must show working. Please i beg can someone help me!!!

Answer 1

Explanation:

Triangle DOE is isosceles. So OED and ODE has same angle.

Total angle for isosceles triangle is 180.

ODE + OED = 180 - 68 = 112

OED = ODE = 112 /2 = 56

Answer 2

EDC = 56 degrees

Explanation:

triangle OED is isosceles : base angles are congruent

2 * EDC + 68 = 180

2 * EDC = 180 - 68

2 * EDC = 112

2/2 EDC = 112/2

EDC = 56 degrees