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Triangle XYZ has vertices X: (0,2) Y: (3,8), and Z: (6,2). Show that the triangle is isosceles by determining the length of each side.

Please help!!!!

1 Answer

3 votes

Answer:

given below

Explanation:

formula used=
√((x2-x1)^2+(y2-y1)^2)

XY=
√((3-0)^2+(8-2)^2) =
√(9+36) =√(45) (here x1=0, x2=3, y1=2, y2=8)

YZ=
√((6-3)^2+(2-8)^2) =
√(9+36) = √(45)

ZX=
√((6-0)^2+(2-2)^2) =
√(36+0) = √(36)

as you can see side XY=YZ=45

so triangle XYZ is an isosceles triangle

hope this helps :)

User Jason Moore
by
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