Question

Triangle XYZ has vertices X: (0,2) Y: (3,8), and Z: (6,2). Show that the triangle is isosceles by determining the length of each side.

Please help!!!!

Answer 1

given below

Explanation:

formula used=
`√((x2-x1)^2+(y2-y1)^2)`

XY=
`√((3-0)^2+(8-2)^2)` =
`√(9+36) =√(45)` (here x1=0, x2=3, y1=2, y2=8)

YZ=
`√((6-3)^2+(2-8)^2)` =
`√(9+36) = √(45)`

ZX=
`√((6-0)^2+(2-2)^2)` =
`√(36+0) = √(36)`

as you can see side XY=YZ=45

so triangle XYZ is an isosceles triangle

hope this helps :)