Answer:
2Fe + Cl(sub2) ---> 2FeCl
Step-by-step explanation:
Before balancing, there is 1 Fe and 2 Cl on the left side of the equation. In order to get 2 Cl on the right side, we have to multiply (FeCl) by 2. This causes there to be 2 Fe on the right side also, so now you go back and multiply 2 by the Fe on the left. Leaving you with 2 Fe and 2 Cl on the left, and 2 Fe and 2 Cl on the right.