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Liquefied petroleum (LP) gas burns according to the following exothermic reaction: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)ΔH∘rxn=−2044kJ What mass of LP gas is necessary to heat 1.3 L of water from room temperature
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Aug 2, 2023
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Liquefied petroleum (LP) gas burns according to the following exothermic reaction:
C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)ΔH∘rxn=−2044kJ
What mass of LP gas is necessary to heat 1.3 L of water from room temperature (25.0 ∘C ) to boiling (100.0 ∘C )? Assume that, during heating, 15% of the heat emitted by the LP gas combustion goes to heat the water. The rest is lost as heat to the surroundings.
Express your answer using two significant figures.
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Awgy
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Answer:
вау, это кажется сложным, но я все равно не знаю
Adam Siwiec
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Aug 7, 2023
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