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Liquefied petroleum (LP) gas burns according to the following exothermic reaction: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)ΔH∘rxn=−2044kJ What mass of LP gas is necessary to heat 1.3 L of water from room temperature
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Liquefied petroleum (LP) gas burns according to the following exothermic reaction:

C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)ΔH∘rxn=−2044kJ

What mass of LP gas is necessary to heat 1.3 L of water from room temperature (25.0 ∘C ) to boiling (100.0 ∘C )? Assume that, during heating, 15% of the heat emitted by the LP gas combustion goes to heat the water. The rest is lost as heat to the surroundings.
Express your answer using two significant figures.

User Awgy
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6 votes

Answer:

вау, это кажется сложным, но я все равно не знаю

User Adam Siwiec
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