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seith's age is 3 years more twice his brother's age. The sum of their ages is 24. Find each of their ages

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Okay so S stands for Seith and B stands for the brother.
You start be writing the equations implied. The first equation is S=2B+3 and the second is S+B=24. You substitute the first equation into the second. Which gives you 2B+3+B=24 adding it together gives you 3B+3=24
3B=21
B=7. So the brother’s age is 7 and when you sub that into the second equation you find that S=17. So the brother’s age is 7 and Seith’s age is 17
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