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Find the equation of the line the (2, 6) and is perpendicular to the equation y = 2x + 8

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Answer: y= -1/2x+7

Step-by-step explanation: use the point slope form and use the -1/2x like the slope because the perpendicular lines are negative reciprocals.

User M Abubaker Majeed
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Answer:

y = -0.5x + 7

Explanation:

Equation of a Line is y = mx + c

where m is the slope and c is the y-intercept

Given two lines are Perpendicular

Then
m_(1) m_(2) =-1

So we given Line whose Equation is y = 2x +8

Then
m_(1) =2 (Coefficient of x)

Since the Line we want is Perpendicular to that line

Then
m_(1) m_(2) =-1 ,
2m_(2) =-1 , m_(2) =(-1)/(2)

So the Equation of the required Line is y = -0.5x +c

Since the Line passes through (2 , 6) , Then y = 6 when x = 2

By substitution , 6 = -0.5*2 + c , 6 = -1 + c

Then c = 6+1 =7

Then the Equation will be y = -0.5x + 7

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