Question

270g of glucose no.of molecules
Next question: 40g of ammonium nitrate

Answer 1

Question 1. There are
`9.025*10^(23)` molecules in 270g of glucose.

Question 2. There are
`3.009*10^(23)` molecules in 40g of glucose.

Step-by-step explanation:

Question 1. 270g of glucose, no. of molecules.

1. Find the chemical formula of glucose.

Formula:
`C_(6) H_(12) O_(6)`

2. Find the molar mass of this compound.

Using the molar mass of each element, which can be found in the periodic table, we make the following calculations:

Molar mass of C: 12.011 u

Total mass of C in compound: (12.011 * 6)= 72.066

Molar mass of H: 1.008 u

Total mass of H in compound: (1.008 * 12)= 12.096

Molar mass of O: 15.999 u

Total mass of O in compound: (15.999 * 6)= 95.994

Why did we multiply the molar mass of C, H and O by 6, 12, and 6? This is because the formula contains 6, 12, and 6 atoms of each element, respectively.

Add up all masses:

72.066 + 12.096 + 95.994= 180.156 g/mole

This result means that 1 mole of glucose has a mass of 180.156 grams.

3. Calculate the number of molecules.

Furthermore, 1 mole of any compound has a total of
`6.022*10^(23)` molecules. To find the amount of molecules, find the amount of moles and then the amount of molecules. Do it in the following fashion:

180.156g -----> 1 mole

270g -----------> x

`(270*1)/(180.156) =1.499`

270 grams of glucose is the equivalent of 1.499 moles of said compound.

Now, find the number of molecules using the amount of moles calculated previously.

180.156g ---->
`6.022*10^(23)`

270g ---------> x

`((270*6.022*10^(23) ))/(180.156) =9.025*10^(23)`

4. Conclusion.

There are
`9.025*10^(23)` molecules in 270g of glucose.

Question 2. 40g of ammonium nitrate, no. of molecules.

Repeat the same process explained previously:

`NH_(4) NO_(3)`

N: 14.007 u

N: 14.007 u

O: (15.999 * 3)= 47.997 u

14.007 + 4.032 + 14.007 + 47.997= 80.043 g/mole

80.043g ---->
`6.022*10^(23)`

40g -----------> x

`x=((40*6.022*10^(23)) )/(80.043) =3.009*10^(23)`

There are
`3.009*10^(23)` molecules in 40g of glucose.