202k views
2 votes
Walter's homemade catapult threw a ball

4 in. farther than 3 times the distance
that Jim's catapult threw the ball. If the
difference between the two distances
was 56 in., how far did Walter's catapult
throw the ball? Write as a equation

2 Answers

4 votes
The equation would be 56/7=8
User DaniPaniz
by
5.3k points
4 votes

Answer:

56 ÷ 7 = 8

Explanation:

4 + 3 = 7

56 ÷ 7 = 8

hopefully thats correct.

User Avi Marcus
by
4.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.