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A=P(1+r/100)^n express r in terms of A,P, and n​

User SpaceBear
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6 votes

Answer:


\huge{ \boxed{r =100( \sqrt[n]{ (A)/(P) } - 1)}}

Explanation:


A = P(1 + (r)/(100) )^(n) \\

First of all in order to make r the subject we have to first divide both sides of the equation by P

That's


(A)/(P) = \frac{P( {1 + (r)/(100) })^(n) }{P} \\

We'll finally get


(A)/(P) = ( {1 + (r)/(100)) }^(n) \\

Next we have to remove the power n and to do that we find the square root of 'n' of both sides as

We have


\sqrt[n]{ (A)/(P) } = \sqrt[n]{( {1 + (r)/(100) })^(n) } \\ \\ \\ \sqrt[n]{ (A)/(P) } = 1 + (r)/(100)

Next we subtract 1 from both sides to isolate r/100

We have


\sqrt[n]{ (A)/(P) } - 1 = 1 - 1 + (r)/(100) \\ \sqrt[n]{ (A)/(P) } - 1 = (r)/(100)

Finally to isolate r , we multiply both sides by 100


(r)/(100) * 100 =100 * (\sqrt[n]{ (A)/(P) } - 1)

We have the final answer as


r =100( \sqrt[n]{ (A)/(P) } - 1) \\

Hope this helps you

User Sjishan
by
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