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If you pay $0.82 for every $1,000 of earthquake coverage, how much would $15,000 of coverage be? $12.30 $820 $1,219 $12,300
asked
Feb 27, 2023
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If you pay $0.82 for every $1,000 of earthquake coverage, how much would $15,000 of coverage be?
$12.30
$820
$1,219
$12,300
Mathematics
college
Stephencelis
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Stephencelis
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$.82/$1000
This is what it says on that first part
Then to solve for coverage on $15,000
.82/1000=x/15,000
12,300= 1000x
12.3= x
Or simply just do .82(15)= 12.3
Qianjigui
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Mar 2, 2023
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820
Explanation: it is .82x (1,000/15,000)
Ivan Gerasimenko
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Mar 6, 2023
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Ivan Gerasimenko
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