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3 votes
3 votes
Abby feeds her dog 1 1/2 cups of food each day, and Braxton feeds his dog 4 1/2 cups of food each day. In one week, how many times more dog food does Braxton’s dog eat when compared with Abby’s dog?

Braxton’s dog eats 5 times more food.
Braxton’s dog eats 3 times more food.
Braxton’s dog eats 4 times more food.
Braxton’s dog eats 2 times more food.

User James Paul Mason
by
2.8k points

2 Answers

13 votes
13 votes
  • Abby's dog eats each day=1 1/2=3/2=1.5cups
  • Braxtons dog eats each day=4 1/2=9/2=4.5cups

Find ratio


\\ \tt\hookrightarrow (4.5)/(1.5)=3

Braxtons dog eats 3times more than Abbys

User Falcojr
by
3.2k points
18 votes
18 votes

Solution:

Note that:

  • Abby's dog: 1.5 cups of food
  • Braxton's dog: 4.5 cups of food

Looking at the information we got, we can say that Braxton's dog eats more. Let's put them into ratio form (Braxton's dog:Abby's dog)

  • => (Braxton's dog:Abby's dog) = 4.5:1.5

Now, put them into fractions.

  • => 4.5:1.5 = 4.5/1.5 = 3

We can conclude that Braxton's dog eats 3 times more food.

User Tim Ottinger
by
2.9k points