1 Answer

MyCatsNameIsBernie · Answer 1 · 2023-09-10T05:48:45+0000

Solution

For this case we can do the following:

$SA=4\pi r^(2)$

Replacing we got:

$SA_1=4\pi(4\operatorname{mm})^2=201.06\operatorname{mm}^(2)$
$SA_2=4\pi(5\operatorname{mm})^2=314.16\operatorname{mm}^(2)$

Then the surface area for the first one is 201.06mm² and the second one 314.16mm²

And the volume is:

$V_1=(4)/(3)\pi(4\operatorname{mm})^3=268.083\operatorname{mm}^(3)$
$V_2=(4)/(3)\pi(5\operatorname{mm})^3=523.599\operatorname{mm}^(3)$

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