Question

Find the area. Round to the nearest hundredth when necessary. 16 in Area in? 2

Answer 1

We have the next figure

Because we have an irregular figure we divide the figure into a rectangle and in a triangle

For the area of the rectangle

`A=l* w`

l=length

w= width

In our case

l=19

w=16

we substitute the values

`A=19*16=304in^2`

for the area of the triangle

`A=(b* h)/(2)`

b= base

h=height

in our case

b=16in

h=30-19=11in

we substitute the values

`\begin{gathered} A=(16*11)/(2) \\ A=88in^2 \end{gathered}`

Then we sum the areas of the figures and we obtain the total are

`\begin{gathered} A=304+88 \\ A=392in^2 \end{gathered}`