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Find the equation of the line that passes through the point (6, 14) and is parallel to y = -4/3x - 1

User Autonomous
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1 Answer

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We will find that line as follows:

*First, we replace the values in the following expression:


y-y_1=m(x-x_1)

We are given a point with x & y components and a line that has a slope of -4/3, now we replace:


y-14=-(4)/(3)(x-6)

Now, we solve for y:


\Rightarrow y-14=-(4)/(3)x+8\Rightarrow y=-(4)/(3)x+22

So, the equation of a line that is parallel to y = -4/3x - 1 that passes through the point (6,

User Hlorand
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