Question

Find the equation of the line that passes through the point (6, 14) and is parallel to y = -4/3x - 1

Answer 1

We will find that line as follows:

*First, we replace the values in the following expression:

`y-y_1=m(x-x_1)`

We are given a point with x & y components and a line that has a slope of -4/3, now we replace:

`y-14=-(4)/(3)(x-6)`

Now, we solve for y:

`\Rightarrow y-14=-(4)/(3)x+8\Rightarrow y=-(4)/(3)x+22`

So, the equation of a line that is parallel to y = -4/3x - 1 that passes through the point (6,