Question

How many individual oxygen atoms are contained in a sample of P₂O5 that also contains 0.620 moles of P?

Answer 1

`9.33*10^(23)atoms`

Explanations:

Given the following parameters:

Moles of Phosphorous = 0.620 moles

According to the compound, for every 2 moles of Phosphorous, there are 5 moles of Oxygen, hence the moles of oxygen contained is given as:

`\begin{gathered} moles\text{ of O}=0.620\cancel{moles\text{ of P}}*\frac{5moles\text{ of O}}{2\cancel{moles\text{ of P}}} \\ moles\text{ }of\text{ O}=1.55moles\text{ of O} \\ \end{gathered}`

According to Avogadro's constant

1 mole = 6.02 * 10^23 atoms

1.55moles of O = 1.55 * 6.02 * 10^23 atoms

1.55moles of O = 9.33 * 10^23 atoms

Hence the individual oxygen atoms contained in a sample of P2O5 that also contains 0.620 moles of P is 9.33 * 10^23 atoms