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Solve by using square roots x^(2)-14=11

User Boblin
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1 Answer

4 votes

Given the Quadratic Equation:


x^2-14=11

You can solve it as follows:

1. Apply the Addition Property of Equality by adding 14 to both sides of the equation:


x^2-14+\((14)\)=11+(14)
x^2=25

2. By definition, the square root undoes the effect of exponent 2 on the variable. Then, you have to take the square root of both sides of the equation:


√(x^2)=\pm√(25)
x=\pm√(25)

3. Notice that you can split the equations into two equations:


x_1=√(25)
x_2=-√(25)

4. Knowing that:


√(25)=5

You get:


x_1=√(25)=5
x_2=-√(25)=-5

Hence, the answer is:


\begin{gathered} x_1=5 \\ x_2=-5 \end{gathered}

User Brenton Alker
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