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Answer question number 17. The question is in the image.

Answer question number 17. The question is in the image.-example-1
Answer question number 17. The question is in the image.-example-1
Answer question number 17. The question is in the image.-example-2

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A trigonometric function (sin or cos) can be written as


g(x)=A\cos(\omega t)\text{ or }g(x)=A\sin(\omega t)

Where A is the amplitude and ω is


\omega=(2\pi)/(T)

Where T is the period of the function.

Then, let's see the function in 20.


g(x)=(1)/(2)\cos(4\pi x)

The amplitude of the function 1/2, let's find the period


\begin{gathered} 4\pi=\omega \\ \\ 4\pi=(2\pi)/(T) \end{gathered}

Solve it for T


\begin{gathered} T=(2\pi)/(4\pi) \\ \\ T=(1)/(2) \end{gathered}

Therefore, the period of the function is 1/2, now we can graph the function, the parent function will be cos(x):

To graph


g(x)=(1)/(2)\cos(4\pi x)

We have to modify the amplitude to 1/2, therefore

Now, we have to modify the period, the function will be period in 1/2, then

Final answer:

Answer question number 17. The question is in the image.-example-1
Answer question number 17. The question is in the image.-example-2
Answer question number 17. The question is in the image.-example-3
Answer question number 17. The question is in the image.-example-4
User Matthewtole
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